Line slope calculator x+y=16


Enter coordinates of two different points:

Straight line given by points A[6; 10] and B[8; 8]

Calculation:

Slope-intercept form of line: y = -x+16

Canonical form of the line equation: x+y-16 = 0

Parametric form of the line equation:
x = t+6
y = -t+10      ; t ∈ R

Slope: m = -1

Slope angle of line: φ = -45° = -0.7854 rad

X intercept: x0 = 16

Y intercept: y0 = q = 16

Distance line from the origin: d0 = 11.3137

The length of the segment AB: |AB| = 2.8284

Vector: AB = (2; -2)

Normal vector: n = (1; 1)

Midpoint of the segment AB: M = [7; 9]

Perpendicular Bisector equation: 2x-2y+4 = 0


Vector OA = (6; 10) ;   |OA| = 11.6619
Vector OB = (8; 8) ;   |OB| = 11.3137
Scalar product OA .OB = 128
Angle ∠ AOB = 14°2'10″ = 0.245 rad