Line slope calculator x+y=16
Straight line given by points A[6; 10] and B[8; 8]
Calculation:
Slope: m = -1Slope-intercept form of line: y = -x+16
Canonical form of the line equation: x+y-16 = 0
Parametric form of the line equation:
x = t+6
y = -t+10 ; t ∈ R
Slope angle of line: φ = -45° = -0.7854 rad
X intercept: x0 = 16
Y intercept: y0 = q = 16
Distance line from the origin: d0 = 11.3137
The length of the segment AB: |AB| = 2.8284
Vector: AB = (2; -2)
Normal vector: n = (1; 1)
Midpoint of the segment AB: M = [7; 9]
Perpendicular Bisector equation: 2x-2y+4 = 0
Vector OA = (6; 10) ; |OA| = 11.6619
Vector OB = (8; 8) ; |OB| = 11.3137
Scalar product OA .OB = 128
Angle ∠ AOB = 14°2'10″ = 0.245 rad