Line slope calculator 10x+3y=90


Enter coordinates of two different points:

Straight line given by points A[6; 10] and B[9; 0]

Calculation:

Slope-intercept form of line: y = -3.3333x+30

Canonical form of the line equation: 10x+3y-90 = 0

Parametric form of the line equation:
x = 3t+6
y = -10t+10      ; t ∈ R

Slope: m = -3.3333

Slope angle of line: φ = -73°18'3″ = -1.2793 rad

X intercept: x0 = 9

Y intercept: y0 = q = 30

Distance line from the origin: d0 = 8.6204

The length of the segment AB: |AB| = 10.4403

Vector: AB = (3; -10)

Normal vector: n = (10; 3)

Midpoint of the segment AB: M = [7.5; 5]

Perpendicular Bisector equation: 3x-10y+27.5 = 0


Vector OA = (6; 10) ;   |OA| = 11.6619
Vector OB = (9; 0) ;   |OB| = 9
Scalar product OA .OB = 54
Angle ∠ AOB = 59°2'10″ = 1.0304 rad