Line slope calculator 10x+3y=90
Straight line given by points A[6; 10] and B[9; 0]
Calculation:
Slope: m = -3.3333Slope-intercept form of line: y = -3.3333x+30
Canonical form of the line equation: 10x+3y-90 = 0
Parametric form of the line equation:
x = 3t+6
y = -10t+10 ; t ∈ R
Slope angle of line: φ = -73°18'3″ = -1.2793 rad
X intercept: x0 = 9
Y intercept: y0 = q = 30
Distance line from the origin: d0 = 8.6204
The length of the segment AB: |AB| = 10.4403
Vector: AB = (3; -10)
Normal vector: n = (10; 3)
Midpoint of the segment AB: M = [7.5; 5]
Perpendicular Bisector equation: 3x-10y+27.5 = 0
Vector OA = (6; 10) ; |OA| = 11.6619
Vector OB = (9; 0) ; |OB| = 9
Scalar product OA .OB = 54
Angle ∠ AOB = 59°2'10″ = 1.0304 rad