Line slope calculator 8x+3y=78
Straight line given by points A[6; 10] and B[9; 2]
Calculation:
Slope: m = -2.6667Slope-intercept form of line: y = -2.6667x+26
Canonical form of the line equation: 8x+3y-78 = 0
Parametric form of the line equation:
x = 3t+6
y = -8t+10 ; t ∈ R
Slope angle of line: φ = -69°26'38″ = -1.212 rad
X intercept: x0 = 9.75
Y intercept: y0 = q = 26
Distance line from the origin: d0 = 9.1292
The length of the segment AB: |AB| = 8.544
Vector: AB = (3; -8)
Normal vector: n = (8; 3)
Midpoint of the segment AB: M = [7.5; 6]
Perpendicular Bisector equation: 3x-8y+25.5 = 0
Vector OA = (6; 10) ; |OA| = 11.6619
Vector OB = (9; 2) ; |OB| = 9.2195
Scalar product OA .OB = 74
Angle ∠ AOB = 46°30'27″ = 0.8117 rad