Line slope calculator 5x+3y=60


Enter coordinates of two different points:

Straight line given by points A[6; 10] and B[9; 5]

Calculation:

Slope-intercept form of line: y = -1.6667x+20

Canonical form of the line equation: 5x+3y-60 = 0

Parametric form of the line equation:
x = 3t+6
y = -5t+10      ; t ∈ R

Slope: m = -1.6667

Slope angle of line: φ = -59°2'10″ = -1.0304 rad

X intercept: x0 = 12

Y intercept: y0 = q = 20

Distance line from the origin: d0 = 10.2899

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; -5)

Normal vector: n = (5; 3)

Midpoint of the segment AB: M = [7.5; 7.5]

Perpendicular Bisector equation: 3x-5y+15 = 0


Vector OA = (6; 10) ;   |OA| = 11.6619
Vector OB = (9; 5) ;   |OB| = 10.2956
Scalar product OA .OB = 104
Angle ∠ AOB = 29°58'54″ = 0.5233 rad