Line slope calculator 4x+3y=54
Straight line given by points A[6; 10] and B[9; 6]
Calculation:
Slope: m = -1.3333Slope-intercept form of line: y = -1.3333x+18
Canonical form of the line equation: 4x+3y-54 = 0
Parametric form of the line equation:
x = 3t+6
y = -4t+10 ; t ∈ R
Slope angle of line: φ = -53°7'48″ = -0.9273 rad
X intercept: x0 = 13.5
Y intercept: y0 = q = 18
Distance line from the origin: d0 = 10.8
The length of the segment AB: |AB| = 5
Vector: AB = (3; -4)
Normal vector: n = (4; 3)
Midpoint of the segment AB: M = [7.5; 8]
Perpendicular Bisector equation: 3x-4y+9.5 = 0
Vector OA = (6; 10) ; |OA| = 11.6619
Vector OB = (9; 6) ; |OB| = 10.8167
Scalar product OA .OB = 114
Angle ∠ AOB = 25°20'46″ = 0.4424 rad