Line slope calculator 2x+3y=42


Enter coordinates of two different points:

Straight line given by points A[6; 10] and B[9; 8]

Calculation:

Slope-intercept form of line: y = -0.6667x+14

Canonical form of the line equation: 2x+3y-42 = 0

Parametric form of the line equation:
x = 3t+6
y = -2t+10      ; t ∈ R

Slope: m = -0.6667

Slope angle of line: φ = -33°41'24″ = -0.588 rad

X intercept: x0 = 21

Y intercept: y0 = q = 14

Distance line from the origin: d0 = 11.6487

The length of the segment AB: |AB| = 3.6056

Vector: AB = (3; -2)

Normal vector: n = (2; 3)

Midpoint of the segment AB: M = [7.5; 9]

Perpendicular Bisector equation: 3x-2y-4.5 = 0


Vector OA = (6; 10) ;   |OA| = 11.6619
Vector OB = (9; 8) ;   |OB| = 12.0416
Scalar product OA .OB = 134
Angle ∠ AOB = 17°24'10″ = 0.3037 rad