Line slope calculator 3x-y=16


Enter coordinates of two different points:

Straight line given by points A[6; 2] and B[7; 5]

Calculation:

Slope-intercept form of line: y = 3x-16

Canonical form of the line equation: 3x-y-16 = 0

Parametric form of the line equation:
x = t+6
y = 3t+2      ; t ∈ R

Slope: m = 3

Slope angle of line: φ = 71°33'54″ = 1.249 rad

X intercept: x0 = 5.3333

Y intercept: y0 = q = -16

Distance line from the origin: d0 = 5.0596

The length of the segment AB: |AB| = 3.1623

Vector: AB = (1; 3)

Normal vector: n = (3; -1)

Midpoint of the segment AB: M = [6.5; 3.5]

Perpendicular Bisector equation: x+3y-17 = 0


Vector OA = (6; 2) ;   |OA| = 6.3246
Vector OB = (7; 5) ;   |OB| = 8.6023
Scalar product OA .OB = 52
Angle ∠ AOB = 17°6'10″ = 0.2985 rad