Line slope calculator 3x+4y=34
Straight line given by points A[6; 4] and B[10; 1]
Calculation:
Slope: m = -0.75Slope-intercept form of line: y = -0.75x+8.5
Canonical form of the line equation: 3x+4y-34 = 0
Parametric form of the line equation:
x = 4t+6
y = -3t+4 ; t ∈ R
Slope angle of line: φ = -36°52'12″ = -0.6435 rad
X intercept: x0 = 11.3333
Y intercept: y0 = q = 8.5
Distance line from the origin: d0 = 6.8
The length of the segment AB: |AB| = 5
Vector: AB = (4; -3)
Normal vector: n = (3; 4)
Midpoint of the segment AB: M = [8; 2.5]
Perpendicular Bisector equation: 4x-3y-24.5 = 0
Vector OA = (6; 4) ; |OA| = 7.2111
Vector OB = (10; 1) ; |OB| = 10.0499
Scalar product OA .OB = 64
Angle ∠ AOB = 27°58'46″ = 0.4883 rad