Line slope calculator 4x+y=29


Enter coordinates of two different points:

Straight line given by points A[6; 5] and B[7; 1]

Calculation:

Slope-intercept form of line: y = -4x+29

Canonical form of the line equation: 4x+y-29 = 0

Parametric form of the line equation:
x = t+6
y = -4t+5      ; t ∈ R

Slope: m = -4

Slope angle of line: φ = -75°57'50″ = -1.3258 rad

X intercept: x0 = 7.25

Y intercept: y0 = q = 29

Distance line from the origin: d0 = 7.0335

The length of the segment AB: |AB| = 4.1231

Vector: AB = (1; -4)

Normal vector: n = (4; 1)

Midpoint of the segment AB: M = [6.5; 3]

Perpendicular Bisector equation: x-4y+5.5 = 0


Vector OA = (6; 5) ;   |OA| = 7.8102
Vector OB = (7; 1) ;   |OB| = 7.0711
Scalar product OA .OB = 47
Angle ∠ AOB = 31°40'32″ = 0.5528 rad