Line slope calculator 4x+3y=39


Enter coordinates of two different points:

Straight line given by points A[6; 5] and B[9; 1]

Calculation:

Slope-intercept form of line: y = -1.3333x+13

Canonical form of the line equation: 4x+3y-39 = 0

Parametric form of the line equation:
x = 3t+6
y = -4t+5      ; t ∈ R

Slope: m = -1.3333

Slope angle of line: φ = -53°7'48″ = -0.9273 rad

X intercept: x0 = 9.75

Y intercept: y0 = q = 13

Distance line from the origin: d0 = 7.8

The length of the segment AB: |AB| = 5

Vector: AB = (3; -4)

Normal vector: n = (4; 3)

Midpoint of the segment AB: M = [7.5; 3]

Perpendicular Bisector equation: 3x-4y-10.5 = 0


Vector OA = (6; 5) ;   |OA| = 7.8102
Vector OB = (9; 1) ;   |OB| = 9.0554
Scalar product OA .OB = 59
Angle ∠ AOB = 33°27'55″ = 0.5841 rad