Line slope calculator 2x+3y=27
Straight line given by points A[6; 5] and B[9; 3]
Calculation:
Slope: m = -0.6667Slope-intercept form of line: y = -0.6667x+9
Canonical form of the line equation: 2x+3y-27 = 0
Parametric form of the line equation:
x = 3t+6
y = -2t+5 ; t ∈ R
Slope angle of line: φ = -33°41'24″ = -0.588 rad
X intercept: x0 = 13.5
Y intercept: y0 = q = 9
Distance line from the origin: d0 = 7.4885
The length of the segment AB: |AB| = 3.6056
Vector: AB = (3; -2)
Normal vector: n = (2; 3)
Midpoint of the segment AB: M = [7.5; 4]
Perpendicular Bisector equation: 3x-2y-14.5 = 0
Vector OA = (6; 5) ; |OA| = 7.8102
Vector OB = (9; 3) ; |OB| = 9.4868
Scalar product OA .OB = 69
Angle ∠ AOB = 21°22'14″ = 0.373 rad