Line slope calculator 3x+4y=42


Enter coordinates of two different points:

Straight line given by points A[6; 6] and B[10; 3]

Calculation:

Slope-intercept form of line: y = -0.75x+10.5

Canonical form of the line equation: 3x+4y-42 = 0

Parametric form of the line equation:
x = 4t+6
y = -3t+6      ; t ∈ R

Slope: m = -0.75

Slope angle of line: φ = -36°52'12″ = -0.6435 rad

X intercept: x0 = 14

Y intercept: y0 = q = 10.5

Distance line from the origin: d0 = 8.4

The length of the segment AB: |AB| = 5

Vector: AB = (4; -3)

Normal vector: n = (3; 4)

Midpoint of the segment AB: M = [8; 4.5]

Perpendicular Bisector equation: 4x-3y-18.5 = 0


Vector OA = (6; 6) ;   |OA| = 8.4853
Vector OB = (10; 3) ;   |OB| = 10.4403
Scalar product OA .OB = 78
Angle ∠ AOB = 28°18'3″ = 0.4939 rad