Line slope calculator 3x+4y=42
Straight line given by points A[6; 6] and B[10; 3]
Calculation:
Slope: m = -0.75Slope-intercept form of line: y = -0.75x+10.5
Canonical form of the line equation: 3x+4y-42 = 0
Parametric form of the line equation:
x = 4t+6
y = -3t+6 ; t ∈ R
Slope angle of line: φ = -36°52'12″ = -0.6435 rad
X intercept: x0 = 14
Y intercept: y0 = q = 10.5
Distance line from the origin: d0 = 8.4
The length of the segment AB: |AB| = 5
Vector: AB = (4; -3)
Normal vector: n = (3; 4)
Midpoint of the segment AB: M = [8; 4.5]
Perpendicular Bisector equation: 4x-3y-18.5 = 0
Vector OA = (6; 6) ; |OA| = 8.4853
Vector OB = (10; 3) ; |OB| = 10.4403
Scalar product OA .OB = 78
Angle ∠ AOB = 28°18'3″ = 0.4939 rad