Line slope calculator x+4y=30
Straight line given by points A[6; 6] and B[10; 5]
Calculation:
Slope: m = -0.25Slope-intercept form of line: y = -0.25x+7.5
Canonical form of the line equation: x+4y-30 = 0
Parametric form of the line equation:
x = 4t+6
y = -t+6 ; t ∈ R
Slope angle of line: φ = -14°2'10″ = -0.245 rad
X intercept: x0 = 30
Y intercept: y0 = q = 7.5
Distance line from the origin: d0 = 7.2761
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; -1)
Normal vector: n = (1; 4)
Midpoint of the segment AB: M = [8; 5.5]
Perpendicular Bisector equation: 4x-y-26.5 = 0
Vector OA = (6; 6) ; |OA| = 8.4853
Vector OB = (10; 5) ; |OB| = 11.1803
Scalar product OA .OB = 90
Angle ∠ AOB = 18°26'6″ = 0.3218 rad