Line slope calculator 5x+y=36
Straight line given by points A[6; 6] and B[7; 1]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+36
Canonical form of the line equation: 5x+y-36 = 0
Parametric form of the line equation:
x = t+6
y = -5t+6 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 7.2
Y intercept: y0 = q = 36
Distance line from the origin: d0 = 7.0602
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [6.5; 3.5]
Perpendicular Bisector equation: x-5y+11 = 0
Vector OA = (6; 6) ; |OA| = 8.4853
Vector OB = (7; 1) ; |OB| = 7.0711
Scalar product OA .OB = 48
Angle ∠ AOB = 36°52'12″ = 0.6435 rad