Line slope calculator 5x+3y=48
Straight line given by points A[6; 6] and B[9; 1]
Calculation:
Slope: m = -1.6667Slope-intercept form of line: y = -1.6667x+16
Canonical form of the line equation: 5x+3y-48 = 0
Parametric form of the line equation:
x = 3t+6
y = -5t+6 ; t ∈ R
Slope angle of line: φ = -59°2'10″ = -1.0304 rad
X intercept: x0 = 9.6
Y intercept: y0 = q = 16
Distance line from the origin: d0 = 8.2319
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; -5)
Normal vector: n = (5; 3)
Midpoint of the segment AB: M = [7.5; 3.5]
Perpendicular Bisector equation: 3x-5y-5 = 0
Vector OA = (6; 6) ; |OA| = 8.4853
Vector OB = (9; 1) ; |OB| = 9.0554
Scalar product OA .OB = 60
Angle ∠ AOB = 38°39'35″ = 0.6747 rad