Line slope calculator 5x+4y=62


Enter coordinates of two different points:

Straight line given by points A[6; 8] and B[10; 3]

Calculation:

Slope-intercept form of line: y = -1.25x+15.5

Canonical form of the line equation: 5x+4y-62 = 0

Parametric form of the line equation:
x = 4t+6
y = -5t+8      ; t ∈ R

Slope: m = -1.25

Slope angle of line: φ = -51°20'25″ = -0.8961 rad

X intercept: x0 = 12.4

Y intercept: y0 = q = 15.5

Distance line from the origin: d0 = 9.6828

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; -5)

Normal vector: n = (5; 4)

Midpoint of the segment AB: M = [8; 5.5]

Perpendicular Bisector equation: 4x-5y-4.5 = 0


Vector OA = (6; 8) ;   |OA| = 10
Vector OB = (10; 3) ;   |OB| = 10.4403
Scalar product OA .OB = 84
Angle ∠ AOB = 36°25'51″ = 0.6358 rad