Line slope calculator 5x+4y=62
Straight line given by points A[6; 8] and B[10; 3]
Calculation:
Slope: m = -1.25Slope-intercept form of line: y = -1.25x+15.5
Canonical form of the line equation: 5x+4y-62 = 0
Parametric form of the line equation:
x = 4t+6
y = -5t+8 ; t ∈ R
Slope angle of line: φ = -51°20'25″ = -0.8961 rad
X intercept: x0 = 12.4
Y intercept: y0 = q = 15.5
Distance line from the origin: d0 = 9.6828
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; -5)
Normal vector: n = (5; 4)
Midpoint of the segment AB: M = [8; 5.5]
Perpendicular Bisector equation: 4x-5y-4.5 = 0
Vector OA = (6; 8) ; |OA| = 10
Vector OB = (10; 3) ; |OB| = 10.4403
Scalar product OA .OB = 84
Angle ∠ AOB = 36°25'51″ = 0.6358 rad