Line slope calculator 4x+y=32
Straight line given by points A[6; 8] and B[7; 4]
Calculation:
Slope: m = -4Slope-intercept form of line: y = -4x+32
Canonical form of the line equation: 4x+y-32 = 0
Parametric form of the line equation:
x = t+6
y = -4t+8 ; t ∈ R
Slope angle of line: φ = -75°57'50″ = -1.3258 rad
X intercept: x0 = 8
Y intercept: y0 = q = 32
Distance line from the origin: d0 = 7.7611
The length of the segment AB: |AB| = 4.1231
Vector: AB = (1; -4)
Normal vector: n = (4; 1)
Midpoint of the segment AB: M = [6.5; 6]
Perpendicular Bisector equation: x-4y+17.5 = 0
Vector OA = (6; 8) ; |OA| = 10
Vector OB = (7; 4) ; |OB| = 8.0623
Scalar product OA .OB = 74
Angle ∠ AOB = 23°23'7″ = 0.4081 rad