Line slope calculator 4x+3y=48


Enter coordinates of two different points:

Straight line given by points A[6; 8] and B[9; 4]

Calculation:

Slope-intercept form of line: y = -1.3333x+16

Canonical form of the line equation: 4x+3y-48 = 0

Parametric form of the line equation:
x = 3t+6
y = -4t+8      ; t ∈ R

Slope: m = -1.3333

Slope angle of line: φ = -53°7'48″ = -0.9273 rad

X intercept: x0 = 12

Y intercept: y0 = q = 16

Distance line from the origin: d0 = 9.6

The length of the segment AB: |AB| = 5

Vector: AB = (3; -4)

Normal vector: n = (4; 3)

Midpoint of the segment AB: M = [7.5; 6]

Perpendicular Bisector equation: 3x-4y+1.5 = 0


Vector OA = (6; 8) ;   |OA| = 10
Vector OB = (9; 4) ;   |OB| = 9.8489
Scalar product OA .OB = 86
Angle ∠ AOB = 29°10'3″ = 0.5091 rad