Line slope calculator 2x-3y=11


Enter coordinates of two different points:

Straight line given by points A[7; 1] and B[10; 3]

Calculation:

Slope-intercept form of line: y = 0.6667x-3.6667

Canonical form of the line equation: 2x-3y-11 = 0

Parametric form of the line equation:
x = 3t+7
y = 2t+1      ; t ∈ R

Slope: m = 0.6667

Slope angle of line: φ = 33°41'24″ = 0.588 rad

X intercept: x0 = 5.5

Y intercept: y0 = q = -3.6667

Distance line from the origin: d0 = 3.0509

The length of the segment AB: |AB| = 3.6056

Vector: AB = (3; 2)

Normal vector: n = (2; -3)

Midpoint of the segment AB: M = [8.5; 2]

Perpendicular Bisector equation: 3x+2y-29.5 = 0


Vector OA = (7; 1) ;   |OA| = 7.0711
Vector OB = (10; 3) ;   |OB| = 10.4403
Scalar product OA .OB = 73
Angle ∠ AOB = 8°34'9″ = 0.1496 rad