Line slope calculator 5x-3y=32
Straight line given by points A[7; 1] and B[10; 6]
Calculation:
Slope: m = 1.6667Slope-intercept form of line: y = 1.6667x-10.6667
Canonical form of the line equation: 5x-3y-32 = 0
Parametric form of the line equation:
x = 3t+7
y = 5t+1 ; t ∈ R
Slope angle of line: φ = 59°2'10″ = 1.0304 rad
X intercept: x0 = 6.4
Y intercept: y0 = q = -10.6667
Distance line from the origin: d0 = 5.488
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; 5)
Normal vector: n = (5; -3)
Midpoint of the segment AB: M = [8.5; 3.5]
Perpendicular Bisector equation: 3x+5y-43 = 0
Vector OA = (7; 1) ; |OA| = 7.0711
Vector OB = (10; 6) ; |OB| = 11.6619
Scalar product OA .OB = 76
Angle ∠ AOB = 22°50'1″ = 0.3985 rad