Line slope calculator 5x+3y=65


Enter coordinates of two different points:

Straight line given by points A[7; 10] and B[10; 5]

Calculation:

Slope-intercept form of line: y = -1.6667x+21.6667

Canonical form of the line equation: 5x+3y-65 = 0

Parametric form of the line equation:
x = 3t+7
y = -5t+10      ; t ∈ R

Slope: m = -1.6667

Slope angle of line: φ = -59°2'10″ = -1.0304 rad

X intercept: x0 = 13

Y intercept: y0 = q = 21.6667

Distance line from the origin: d0 = 11.1474

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; -5)

Normal vector: n = (5; 3)

Midpoint of the segment AB: M = [8.5; 7.5]

Perpendicular Bisector equation: 3x-5y+12 = 0


Vector OA = (7; 10) ;   |OA| = 12.2066
Vector OB = (10; 5) ;   |OB| = 11.1803
Scalar product OA .OB = 120
Angle ∠ AOB = 28°26'35″ = 0.4964 rad