Line slope calculator 5x+3y=65
Straight line given by points A[7; 10] and B[10; 5]
Calculation:
Slope: m = -1.6667Slope-intercept form of line: y = -1.6667x+21.6667
Canonical form of the line equation: 5x+3y-65 = 0
Parametric form of the line equation:
x = 3t+7
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -59°2'10″ = -1.0304 rad
X intercept: x0 = 13
Y intercept: y0 = q = 21.6667
Distance line from the origin: d0 = 11.1474
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; -5)
Normal vector: n = (5; 3)
Midpoint of the segment AB: M = [8.5; 7.5]
Perpendicular Bisector equation: 3x-5y+12 = 0
Vector OA = (7; 10) ; |OA| = 12.2066
Vector OB = (10; 5) ; |OB| = 11.1803
Scalar product OA .OB = 120
Angle ∠ AOB = 28°26'35″ = 0.4964 rad