Line slope calculator 4x+3y=58


Enter coordinates of two different points:

Straight line given by points A[7; 10] and B[10; 6]

Calculation:

Slope-intercept form of line: y = -1.3333x+19.3333

Canonical form of the line equation: 4x+3y-58 = 0

Parametric form of the line equation:
x = 3t+7
y = -4t+10      ; t ∈ R

Slope: m = -1.3333

Slope angle of line: φ = -53°7'48″ = -0.9273 rad

X intercept: x0 = 14.5

Y intercept: y0 = q = 19.3333

Distance line from the origin: d0 = 11.6

The length of the segment AB: |AB| = 5

Vector: AB = (3; -4)

Normal vector: n = (4; 3)

Midpoint of the segment AB: M = [8.5; 8]

Perpendicular Bisector equation: 3x-4y+6.5 = 0


Vector OA = (7; 10) ;   |OA| = 12.2066
Vector OB = (10; 6) ;   |OB| = 11.6619
Scalar product OA .OB = 130
Angle ∠ AOB = 24°2'39″ = 0.4197 rad