Line slope calculator 10x+y=80


Enter coordinates of two different points:

Straight line given by points A[7; 10] and B[8; 0]

Calculation:

Slope-intercept form of line: y = -10x+80

Canonical form of the line equation: 10x+y-80 = 0

Parametric form of the line equation:
x = t+7
y = -10t+10      ; t ∈ R

Slope: m = -10

Slope angle of line: φ = -84°17'22″ = -1.4711 rad

X intercept: x0 = 8

Y intercept: y0 = q = 80

Distance line from the origin: d0 = 7.9603

The length of the segment AB: |AB| = 10.0499

Vector: AB = (1; -10)

Normal vector: n = (10; 1)

Midpoint of the segment AB: M = [7.5; 5]

Perpendicular Bisector equation: x-10y+42.5 = 0


Vector OA = (7; 10) ;   |OA| = 12.2066
Vector OB = (8; 0) ;   |OB| = 8
Scalar product OA .OB = 56
Angle ∠ AOB = 55°29″ = 0.9601 rad