Line slope calculator 6x+y=52
Straight line given by points A[7; 10] and B[8; 4]
Calculation:
Slope: m = -6Slope-intercept form of line: y = -6x+52
Canonical form of the line equation: 6x+y-52 = 0
Parametric form of the line equation:
x = t+7
y = -6t+10 ; t ∈ R
Slope angle of line: φ = -80°32'16″ = -1.4056 rad
X intercept: x0 = 8.6667
Y intercept: y0 = q = 52
Distance line from the origin: d0 = 8.5487
The length of the segment AB: |AB| = 6.0828
Vector: AB = (1; -6)
Normal vector: n = (6; 1)
Midpoint of the segment AB: M = [7.5; 7]
Perpendicular Bisector equation: x-6y+34.5 = 0
Vector OA = (7; 10) ; |OA| = 12.2066
Vector OB = (8; 4) ; |OB| = 8.9443
Scalar product OA .OB = 96
Angle ∠ AOB = 28°26'35″ = 0.4964 rad