Line slope calculator 5x+y=45
Straight line given by points A[7; 10] and B[8; 5]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+45
Canonical form of the line equation: 5x+y-45 = 0
Parametric form of the line equation:
x = t+7
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 9
Y intercept: y0 = q = 45
Distance line from the origin: d0 = 8.8252
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [7.5; 7.5]
Perpendicular Bisector equation: x-5y+30 = 0
Vector OA = (7; 10) ; |OA| = 12.2066
Vector OB = (8; 5) ; |OB| = 9.434
Scalar product OA .OB = 106
Angle ∠ AOB = 23°9″ = 0.4015 rad