Line slope calculator 7x-3y=40
Straight line given by points A[7; 3] and B[10; 10]
Calculation:
Slope: m = 2.3333Slope-intercept form of line: y = 2.3333x-13.3333
Canonical form of the line equation: 7x-3y-40 = 0
Parametric form of the line equation:
x = 3t+7
y = 7t+3 ; t ∈ R
Slope angle of line: φ = 66°48'5″ = 1.1659 rad
X intercept: x0 = 5.7143
Y intercept: y0 = q = -13.3333
Distance line from the origin: d0 = 5.2523
The length of the segment AB: |AB| = 7.6158
Vector: AB = (3; 7)
Normal vector: n = (7; -3)
Midpoint of the segment AB: M = [8.5; 6.5]
Perpendicular Bisector equation: 3x+7y-71 = 0
Vector OA = (7; 3) ; |OA| = 7.6158
Vector OB = (10; 10) ; |OB| = 14.1421
Scalar product OA .OB = 100
Angle ∠ AOB = 21°48'5″ = 0.3805 rad