Line slope calculator 4x+3y=43
Straight line given by points A[7; 5] and B[10; 1]
Calculation:
Slope: m = -1.3333Slope-intercept form of line: y = -1.3333x+14.3333
Canonical form of the line equation: 4x+3y-43 = 0
Parametric form of the line equation:
x = 3t+7
y = -4t+5 ; t ∈ R
Slope angle of line: φ = -53°7'48″ = -0.9273 rad
X intercept: x0 = 10.75
Y intercept: y0 = q = 14.3333
Distance line from the origin: d0 = 8.6
The length of the segment AB: |AB| = 5
Vector: AB = (3; -4)
Normal vector: n = (4; 3)
Midpoint of the segment AB: M = [8.5; 3]
Perpendicular Bisector equation: 3x-4y-13.5 = 0
Vector OA = (7; 5) ; |OA| = 8.6023
Vector OB = (10; 1) ; |OB| = 10.0499
Scalar product OA .OB = 75
Angle ∠ AOB = 29°49'37″ = 0.5206 rad