Line slope calculator 2x+3y=29


Enter coordinates of two different points:

Straight line given by points A[7; 5] and B[10; 3]

Calculation:

Slope-intercept form of line: y = -0.6667x+9.6667

Canonical form of the line equation: 2x+3y-29 = 0

Parametric form of the line equation:
x = 3t+7
y = -2t+5      ; t ∈ R

Slope: m = -0.6667

Slope angle of line: φ = -33°41'24″ = -0.588 rad

X intercept: x0 = 14.5

Y intercept: y0 = q = 9.6667

Distance line from the origin: d0 = 8.0432

The length of the segment AB: |AB| = 3.6056

Vector: AB = (3; -2)

Normal vector: n = (2; 3)

Midpoint of the segment AB: M = [8.5; 4]

Perpendicular Bisector equation: 3x-2y-17.5 = 0


Vector OA = (7; 5) ;   |OA| = 8.6023
Vector OB = (10; 3) ;   |OB| = 10.4403
Scalar product OA .OB = 85
Angle ∠ AOB = 18°50'18″ = 0.3288 rad