Line slope calculator 5x+3y=53


Enter coordinates of two different points:

Straight line given by points A[7; 6] and B[10; 1]

Calculation:

Slope-intercept form of line: y = -1.6667x+17.6667

Canonical form of the line equation: 5x+3y-53 = 0

Parametric form of the line equation:
x = 3t+7
y = -5t+6      ; t ∈ R

Slope: m = -1.6667

Slope angle of line: φ = -59°2'10″ = -1.0304 rad

X intercept: x0 = 10.6

Y intercept: y0 = q = 17.6667

Distance line from the origin: d0 = 9.0894

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; -5)

Normal vector: n = (5; 3)

Midpoint of the segment AB: M = [8.5; 3.5]

Perpendicular Bisector equation: 3x-5y-8 = 0


Vector OA = (7; 6) ;   |OA| = 9.2195
Vector OB = (10; 1) ;   |OB| = 10.0499
Scalar product OA .OB = 76
Angle ∠ AOB = 34°53'27″ = 0.609 rad