Line slope calculator 3x+y=27


Enter coordinates of two different points:

Straight line given by points A[7; 6] and B[8; 3]

Calculation:

Slope-intercept form of line: y = -3x+27

Canonical form of the line equation: 3x+y-27 = 0

Parametric form of the line equation:
x = t+7
y = -3t+6      ; t ∈ R

Slope: m = -3

Slope angle of line: φ = -71°33'54″ = -1.249 rad

X intercept: x0 = 9

Y intercept: y0 = q = 27

Distance line from the origin: d0 = 8.5381

The length of the segment AB: |AB| = 3.1623

Vector: AB = (1; -3)

Normal vector: n = (3; 1)

Midpoint of the segment AB: M = [7.5; 4.5]

Perpendicular Bisector equation: x-3y+6 = 0


Vector OA = (7; 6) ;   |OA| = 9.2195
Vector OB = (8; 3) ;   |OB| = 8.544
Scalar product OA .OB = 74
Angle ∠ AOB = 20°2'43″ = 0.3499 rad