Line slope calculator 5x+3y=59


Enter coordinates of two different points:

Straight line given by points A[7; 8] and B[10; 3]

Calculation:

Slope-intercept form of line: y = -1.6667x+19.6667

Canonical form of the line equation: 5x+3y-59 = 0

Parametric form of the line equation:
x = 3t+7
y = -5t+8      ; t ∈ R

Slope: m = -1.6667

Slope angle of line: φ = -59°2'10″ = -1.0304 rad

X intercept: x0 = 11.8

Y intercept: y0 = q = 19.6667

Distance line from the origin: d0 = 10.1184

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; -5)

Normal vector: n = (5; 3)

Midpoint of the segment AB: M = [8.5; 5.5]

Perpendicular Bisector equation: 3x-5y+2 = 0


Vector OA = (7; 8) ;   |OA| = 10.6301
Vector OB = (10; 3) ;   |OB| = 10.4403
Scalar product OA .OB = 94
Angle ∠ AOB = 32°6'53″ = 0.5605 rad