Line slope calculator 5x+y=43
Straight line given by points A[7; 8] and B[8; 3]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+43
Canonical form of the line equation: 5x+y-43 = 0
Parametric form of the line equation:
x = t+7
y = -5t+8 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 8.6
Y intercept: y0 = q = 43
Distance line from the origin: d0 = 8.433
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [7.5; 5.5]
Perpendicular Bisector equation: x-5y+20 = 0
Vector OA = (7; 8) ; |OA| = 10.6301
Vector OB = (8; 3) ; |OB| = 8.544
Scalar product OA .OB = 80
Angle ∠ AOB = 28°15'29″ = 0.4932 rad