Line slope calculator 5x+y=43


Enter coordinates of two different points:

Straight line given by points A[7; 8] and B[8; 3]

Calculation:

Slope-intercept form of line: y = -5x+43

Canonical form of the line equation: 5x+y-43 = 0

Parametric form of the line equation:
x = t+7
y = -5t+8      ; t ∈ R

Slope: m = -5

Slope angle of line: φ = -78°41'24″ = -1.3734 rad

X intercept: x0 = 8.6

Y intercept: y0 = q = 43

Distance line from the origin: d0 = 8.433

The length of the segment AB: |AB| = 5.099

Vector: AB = (1; -5)

Normal vector: n = (5; 1)

Midpoint of the segment AB: M = [7.5; 5.5]

Perpendicular Bisector equation: x-5y+20 = 0


Vector OA = (7; 8) ;   |OA| = 10.6301
Vector OB = (8; 3) ;   |OB| = 8.544
Scalar product OA .OB = 80
Angle ∠ AOB = 28°15'29″ = 0.4932 rad