Line slope calculator 4x-y=32


Enter coordinates of two different points:

Straight line given by points A[8; 0] and B[9; 4]

Calculation:

Slope-intercept form of line: y = 4x-32

Canonical form of the line equation: 4x-y-32 = 0

Parametric form of the line equation:
x = t+8
y = 4t      ; t ∈ R

Slope: m = 4

Slope angle of line: φ = 75°57'50″ = 1.3258 rad

X intercept: x0 = 8

Y intercept: y0 = q = -32

Distance line from the origin: d0 = 7.7611

The length of the segment AB: |AB| = 4.1231

Vector: AB = (1; 4)

Normal vector: n = (4; -1)

Midpoint of the segment AB: M = [8.5; 2]

Perpendicular Bisector equation: x+4y-16.5 = 0


Vector OA = (8; 0) ;   |OA| = 8
Vector OB = (9; 4) ;   |OB| = 9.8489
Scalar product OA .OB = 72
Angle ∠ AOB = 23°57'45″ = 0.4182 rad