Line slope calculator 5x-y=39


Enter coordinates of two different points:

Straight line given by points A[8; 1] and B[9; 6]

Calculation:

Slope-intercept form of line: y = 5x-39

Canonical form of the line equation: 5x-y-39 = 0

Parametric form of the line equation:
x = t+8
y = 5t+1      ; t ∈ R

Slope: m = 5

Slope angle of line: φ = 78°41'24″ = 1.3734 rad

X intercept: x0 = 7.8

Y intercept: y0 = q = -39

Distance line from the origin: d0 = 7.6485

The length of the segment AB: |AB| = 5.099

Vector: AB = (1; 5)

Normal vector: n = (5; -1)

Midpoint of the segment AB: M = [8.5; 3.5]

Perpendicular Bisector equation: x+5y-26 = 0


Vector OA = (8; 1) ;   |OA| = 8.0623
Vector OB = (9; 6) ;   |OB| = 10.8167
Scalar product OA .OB = 78
Angle ∠ AOB = 26°33'54″ = 0.4636 rad