Line slope calculator 10x+y=90


Enter coordinates of two different points:

Straight line given by points A[8; 10] and B[9; 0]

Calculation:

Slope-intercept form of line: y = -10x+90

Canonical form of the line equation: 10x+y-90 = 0

Parametric form of the line equation:
x = t+8
y = -10t+10      ; t ∈ R

Slope: m = -10

Slope angle of line: φ = -84°17'22″ = -1.4711 rad

X intercept: x0 = 9

Y intercept: y0 = q = 90

Distance line from the origin: d0 = 8.9553

The length of the segment AB: |AB| = 10.0499

Vector: AB = (1; -10)

Normal vector: n = (10; 1)

Midpoint of the segment AB: M = [8.5; 5]

Perpendicular Bisector equation: x-10y+41.5 = 0


Vector OA = (8; 10) ;   |OA| = 12.8062
Vector OB = (9; 0) ;   |OB| = 9
Scalar product OA .OB = 72
Angle ∠ AOB = 51°20'25″ = 0.8961 rad