Line slope calculator 5x+y=50
Straight line given by points A[8; 10] and B[9; 5]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+50
Canonical form of the line equation: 5x+y-50 = 0
Parametric form of the line equation:
x = t+8
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 10
Y intercept: y0 = q = 50
Distance line from the origin: d0 = 9.8058
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [8.5; 7.5]
Perpendicular Bisector equation: x-5y+29 = 0
Vector OA = (8; 10) ; |OA| = 12.8062
Vector OB = (9; 5) ; |OB| = 10.2956
Scalar product OA .OB = 122
Angle ∠ AOB = 22°17'8″ = 0.389 rad