Line slope calculator 4x+y=42
Straight line given by points A[8; 10] and B[9; 6]
Calculation:
Slope: m = -4Slope-intercept form of line: y = -4x+42
Canonical form of the line equation: 4x+y-42 = 0
Parametric form of the line equation:
x = t+8
y = -4t+10 ; t ∈ R
Slope angle of line: φ = -75°57'50″ = -1.3258 rad
X intercept: x0 = 10.5
Y intercept: y0 = q = 42
Distance line from the origin: d0 = 10.1865
The length of the segment AB: |AB| = 4.1231
Vector: AB = (1; -4)
Normal vector: n = (4; 1)
Midpoint of the segment AB: M = [8.5; 8]
Perpendicular Bisector equation: x-4y+23.5 = 0
Vector OA = (8; 10) ; |OA| = 12.8062
Vector OB = (9; 6) ; |OB| = 10.8167
Scalar product OA .OB = 132
Angle ∠ AOB = 17°39' = 0.3081 rad