Line slope calculator 5x+y=46
Straight line given by points A[8; 6] and B[9; 1]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+46
Canonical form of the line equation: 5x+y-46 = 0
Parametric form of the line equation:
x = t+8
y = -5t+6 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 9.2
Y intercept: y0 = q = 46
Distance line from the origin: d0 = 9.0213
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [8.5; 3.5]
Perpendicular Bisector equation: x-5y+9 = 0
Vector OA = (8; 6) ; |OA| = 10
Vector OB = (9; 1) ; |OB| = 9.0554
Scalar product OA .OB = 78
Angle ∠ AOB = 30°31'47″ = 0.5328 rad