Line slope calculator 4x+y=40


Enter coordinates of two different points:

Straight line given by points A[8; 8] and B[9; 4]

Calculation:

Slope-intercept form of line: y = -4x+40

Canonical form of the line equation: 4x+y-40 = 0

Parametric form of the line equation:
x = t+8
y = -4t+8      ; t ∈ R

Slope: m = -4

Slope angle of line: φ = -75°57'50″ = -1.3258 rad

X intercept: x0 = 10

Y intercept: y0 = q = 40

Distance line from the origin: d0 = 9.7014

The length of the segment AB: |AB| = 4.1231

Vector: AB = (1; -4)

Normal vector: n = (4; 1)

Midpoint of the segment AB: M = [8.5; 6]

Perpendicular Bisector equation: x-4y+15.5 = 0


Vector OA = (8; 8) ;   |OA| = 11.3137
Vector OB = (9; 4) ;   |OB| = 9.8489
Scalar product OA .OB = 104
Angle ∠ AOB = 21°2'15″ = 0.3672 rad