Line slope calculator 3x+y=32


Enter coordinates of two different points:

Straight line given by points A[8; 8] and B[9; 5]

Calculation:

Slope-intercept form of line: y = -3x+32

Canonical form of the line equation: 3x+y-32 = 0

Parametric form of the line equation:
x = t+8
y = -3t+8      ; t ∈ R

Slope: m = -3

Slope angle of line: φ = -71°33'54″ = -1.249 rad

X intercept: x0 = 10.6667

Y intercept: y0 = q = 32

Distance line from the origin: d0 = 10.1193

The length of the segment AB: |AB| = 3.1623

Vector: AB = (1; -3)

Normal vector: n = (3; 1)

Midpoint of the segment AB: M = [8.5; 6.5]

Perpendicular Bisector equation: x-3y+11 = 0


Vector OA = (8; 8) ;   |OA| = 11.3137
Vector OB = (9; 5) ;   |OB| = 10.2956
Scalar product OA .OB = 112
Angle ∠ AOB = 15°56'43″ = 0.2783 rad