Line slope calculator 3x+y=32
Straight line given by points A[8; 8] and B[9; 5]
Calculation:
Slope: m = -3Slope-intercept form of line: y = -3x+32
Canonical form of the line equation: 3x+y-32 = 0
Parametric form of the line equation:
x = t+8
y = -3t+8 ; t ∈ R
Slope angle of line: φ = -71°33'54″ = -1.249 rad
X intercept: x0 = 10.6667
Y intercept: y0 = q = 32
Distance line from the origin: d0 = 10.1193
The length of the segment AB: |AB| = 3.1623
Vector: AB = (1; -3)
Normal vector: n = (3; 1)
Midpoint of the segment AB: M = [8.5; 6.5]
Perpendicular Bisector equation: x-3y+11 = 0
Vector OA = (8; 8) ; |OA| = 11.3137
Vector OB = (9; 5) ; |OB| = 10.2956
Scalar product OA .OB = 112
Angle ∠ AOB = 15°56'43″ = 0.2783 rad