Line slope calculator 5x+y=55


Enter coordinates of two different points:

Straight line given by points A[9; 10] and B[10; 5]

Calculation:

Slope-intercept form of line: y = -5x+55

Canonical form of the line equation: 5x+y-55 = 0

Parametric form of the line equation:
x = t+9
y = -5t+10      ; t ∈ R

Slope: m = -5

Slope angle of line: φ = -78°41'24″ = -1.3734 rad

X intercept: x0 = 11

Y intercept: y0 = q = 55

Distance line from the origin: d0 = 10.7864

The length of the segment AB: |AB| = 5.099

Vector: AB = (1; -5)

Normal vector: n = (5; 1)

Midpoint of the segment AB: M = [9.5; 7.5]

Perpendicular Bisector equation: x-5y+28 = 0


Vector OA = (9; 10) ;   |OA| = 13.4536
Vector OB = (10; 5) ;   |OB| = 11.1803
Scalar product OA .OB = 140
Angle ∠ AOB = 21°26'52″ = 0.3743 rad