Line slope calculator 5x+y=55
Straight line given by points A[9; 10] and B[10; 5]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+55
Canonical form of the line equation: 5x+y-55 = 0
Parametric form of the line equation:
x = t+9
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 11
Y intercept: y0 = q = 55
Distance line from the origin: d0 = 10.7864
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [9.5; 7.5]
Perpendicular Bisector equation: x-5y+28 = 0
Vector OA = (9; 10) ; |OA| = 13.4536
Vector OB = (10; 5) ; |OB| = 11.1803
Scalar product OA .OB = 140
Angle ∠ AOB = 21°26'52″ = 0.3743 rad