Line slope calculator 8x+y=80
Straight line given by points A[9; 8] and B[10; 0]
Calculation:
Slope: m = -8Slope-intercept form of line: y = -8x+80
Canonical form of the line equation: 8x+y-80 = 0
Parametric form of the line equation:
x = t+9
y = -8t+8 ; t ∈ R
Slope angle of line: φ = -82°52'30″ = -1.4464 rad
X intercept: x0 = 10
Y intercept: y0 = q = 80
Distance line from the origin: d0 = 9.9228
The length of the segment AB: |AB| = 8.0623
Vector: AB = (1; -8)
Normal vector: n = (8; 1)
Midpoint of the segment AB: M = [9.5; 4]
Perpendicular Bisector equation: x-8y+22.5 = 0
Vector OA = (9; 8) ; |OA| = 12.0416
Vector OB = (10; 0) ; |OB| = 10
Scalar product OA .OB = 90
Angle ∠ AOB = 41°38'1″ = 0.7266 rad