Line slope calculator 6x+y=62
Straight line given by points A[9; 8] and B[10; 2]
Calculation:
Slope: m = -6Slope-intercept form of line: y = -6x+62
Canonical form of the line equation: 6x+y-62 = 0
Parametric form of the line equation:
x = t+9
y = -6t+8 ; t ∈ R
Slope angle of line: φ = -80°32'16″ = -1.4056 rad
X intercept: x0 = 10.3333
Y intercept: y0 = q = 62
Distance line from the origin: d0 = 10.1927
The length of the segment AB: |AB| = 6.0828
Vector: AB = (1; -6)
Normal vector: n = (6; 1)
Midpoint of the segment AB: M = [9.5; 5]
Perpendicular Bisector equation: x-6y+20.5 = 0
Vector OA = (9; 8) ; |OA| = 12.0416
Vector OB = (10; 2) ; |OB| = 10.198
Scalar product OA .OB = 106
Angle ∠ AOB = 30°19'25″ = 0.5292 rad