Line slope calculator 5x+y=53


Enter coordinates of two different points:

Straight line given by points A[9; 8] and B[10; 3]

Calculation:

Slope-intercept form of line: y = -5x+53

Canonical form of the line equation: 5x+y-53 = 0

Parametric form of the line equation:
x = t+9
y = -5t+8      ; t ∈ R

Slope: m = -5

Slope angle of line: φ = -78°41'24″ = -1.3734 rad

X intercept: x0 = 10.6

Y intercept: y0 = q = 53

Distance line from the origin: d0 = 10.3942

The length of the segment AB: |AB| = 5.099

Vector: AB = (1; -5)

Normal vector: n = (5; 1)

Midpoint of the segment AB: M = [9.5; 5.5]

Perpendicular Bisector equation: x-5y+18 = 0


Vector OA = (9; 8) ;   |OA| = 12.0416
Vector OB = (10; 3) ;   |OB| = 10.4403
Scalar product OA .OB = 114
Angle ∠ AOB = 24°56'3″ = 0.4352 rad