Line slope calculator 5x+y=53
Straight line given by points A[9; 8] and B[10; 3]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+53
Canonical form of the line equation: 5x+y-53 = 0
Parametric form of the line equation:
x = t+9
y = -5t+8 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 10.6
Y intercept: y0 = q = 53
Distance line from the origin: d0 = 10.3942
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [9.5; 5.5]
Perpendicular Bisector equation: x-5y+18 = 0
Vector OA = (9; 8) ; |OA| = 12.0416
Vector OB = (10; 3) ; |OB| = 10.4403
Scalar product OA .OB = 114
Angle ∠ AOB = 24°56'3″ = 0.4352 rad