Line slope calculator 3x+y=35
Straight line given by points A[9; 8] and B[10; 5]
Calculation:
Slope: m = -3Slope-intercept form of line: y = -3x+35
Canonical form of the line equation: 3x+y-35 = 0
Parametric form of the line equation:
x = t+9
y = -3t+8 ; t ∈ R
Slope angle of line: φ = -71°33'54″ = -1.249 rad
X intercept: x0 = 11.6667
Y intercept: y0 = q = 35
Distance line from the origin: d0 = 11.068
The length of the segment AB: |AB| = 3.1623
Vector: AB = (1; -3)
Normal vector: n = (3; 1)
Midpoint of the segment AB: M = [9.5; 6.5]
Perpendicular Bisector equation: x-3y+10 = 0
Vector OA = (9; 8) ; |OA| = 12.0416
Vector OB = (10; 5) ; |OB| = 11.1803
Scalar product OA .OB = 130
Angle ∠ AOB = 15°4'7″ = 0.263 rad