Algebra problem

This is algebra. Let n represent an unknown number.

1. Eight more than the number n
2. Three times the number n
3. The product of the number n and eight
4. Three less than the number n
5. Three decreased by the number n

Result

a = (Correct answer is: 8+n)
b = (Correct answer is: 3n)
c = (Correct answer is: 8n)
d = (Correct answer is: n-3)
e = (Correct answer is: 3-n)

Solution:

$a=8+n$
$b=3n$
$c=8n$
$d=n-3$
$e=3-n$

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