Seven numbers

Write seven 4-digit numbers that are divisible by 3 and at the same time by 4.

Correct result:

a₁ =  1008
a₂ =  1020
a₃ =  1032
a₄ =  1044
a₅ =  1056
a₆ =  1068
a₇ =  1080

Solution:

$a_2=a_1+d=1008+12=1020$

$a_3=a_2+d=1020+12=1032$

$a_4=a_3+d=1032+12=1044$

$a_5=a_4+d=1044+12=1056$

$a_6=a_5+d=1056+12=1068$

$a_7=a_6+d=1068+12=1080$

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