# Divide 8

Divide 6840 by x y and z, in such a way that x has twice as much as y, who has half as much as z

Result

x =  2736
y =  1368
z =  2736

#### Solution:

$6840=x+y+z \ \\ x=2y \ \\ 2y=z \ \\ \ \\ 6840=x + (x/2)+ (2y) \ \\ 6840=x + (x/2) + x \ \\ \ \\ 6840=x + (x/2) + x \ \\ \ \\ 5x=13680 \ \\ \ \\ x=2736 \ \\ =2736$
$y=x/2=2736/2=1368$
$z=2 \cdot \ y=2 \cdot \ 1368=2736$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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