What is 16

What is the sum of three consecutive even integers such that six more than twice the second is 2/3 of the first increased by 3/2 of the third?

Correct answer:

s =  78

Step-by-step explanation:

6+2b=2/3 a+3/2 c b=a+2 c=b+2  6+2 b=2/3 a+3/2 c b=a+2 c=b+2  4a12b+9c=36 ab=2 bc=2  Row241 Row1Row2 4a12b+9c=36 2b2.25c=11 bc=2  Row321 Row2Row3 4a12b+9c=36 2b2.25c=11 0.125c=3.5  c=0.1253.5=28 b=211+2.25c=211+2.25 28=26 a=436+12b9c=436+12 269 28=24  a=24 b=26 c=28  s=a+b+c=24+26+28=78

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