# Trio

Trio of workers earn 750 euros. Money divided by the work that each of them made​​.

First received twice as the second, the second received three times more than the third. How many got everyone from workers?

Result

x1 =  450
x2 =  225
x3 =  75

#### Solution:

$x_1=2 \cdot \ 3 \cdot \ (750/(2 \cdot \ 3+3+1))=450 \ \text{Eur}$
$x_2=3 \cdot \ (750/(2 \cdot \ 3+3+1))=225 \ \text{Eur}$
$\ \\ 750 = x_1 + x_2 + x_3 \ \\ 750 = 2 x_2 + x_2 + x_3 \ \\ 750 = 6 x_3 + 3 x_3 + x_3 \ \\ \ \\ 750 = 10x_3 \ \\ \ \\ x_3 = 75 \ \text{Eur} \ \\ x_2 = 3 x_3 = 225 \ Eur \ \\ x_1 = 2 x_2 = 450 \ Eur$

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